(0) Obligation:

The Runtime Complexity (innermost) of the given CpxTRS could be proven to be BOUNDS(1, n^1).


The TRS R consists of the following rules:

active(app(nil, YS)) → mark(YS)
active(app(cons(X, XS), YS)) → mark(cons(X, app(XS, YS)))
active(from(X)) → mark(cons(X, from(s(X))))
active(zWadr(nil, YS)) → mark(nil)
active(zWadr(XS, nil)) → mark(nil)
active(zWadr(cons(X, XS), cons(Y, YS))) → mark(cons(app(Y, cons(X, nil)), zWadr(XS, YS)))
active(prefix(L)) → mark(cons(nil, zWadr(L, prefix(L))))
active(app(X1, X2)) → app(active(X1), X2)
active(app(X1, X2)) → app(X1, active(X2))
active(cons(X1, X2)) → cons(active(X1), X2)
active(from(X)) → from(active(X))
active(s(X)) → s(active(X))
active(zWadr(X1, X2)) → zWadr(active(X1), X2)
active(zWadr(X1, X2)) → zWadr(X1, active(X2))
active(prefix(X)) → prefix(active(X))
app(mark(X1), X2) → mark(app(X1, X2))
app(X1, mark(X2)) → mark(app(X1, X2))
cons(mark(X1), X2) → mark(cons(X1, X2))
from(mark(X)) → mark(from(X))
s(mark(X)) → mark(s(X))
zWadr(mark(X1), X2) → mark(zWadr(X1, X2))
zWadr(X1, mark(X2)) → mark(zWadr(X1, X2))
prefix(mark(X)) → mark(prefix(X))
proper(app(X1, X2)) → app(proper(X1), proper(X2))
proper(nil) → ok(nil)
proper(cons(X1, X2)) → cons(proper(X1), proper(X2))
proper(from(X)) → from(proper(X))
proper(s(X)) → s(proper(X))
proper(zWadr(X1, X2)) → zWadr(proper(X1), proper(X2))
proper(prefix(X)) → prefix(proper(X))
app(ok(X1), ok(X2)) → ok(app(X1, X2))
cons(ok(X1), ok(X2)) → ok(cons(X1, X2))
from(ok(X)) → ok(from(X))
s(ok(X)) → ok(s(X))
zWadr(ok(X1), ok(X2)) → ok(zWadr(X1, X2))
prefix(ok(X)) → ok(prefix(X))
top(mark(X)) → top(proper(X))
top(ok(X)) → top(active(X))

Rewrite Strategy: INNERMOST

(1) NestedDefinedSymbolProof (BOTH BOUNDS(ID, ID) transformation)

The following defined symbols can occur below the 0th argument of top: proper, active
The following defined symbols can occur below the 0th argument of proper: proper, active
The following defined symbols can occur below the 0th argument of active: proper, active

Hence, the left-hand sides of the following rules are not basic-reachable and can be removed:
active(app(nil, YS)) → mark(YS)
active(app(cons(X, XS), YS)) → mark(cons(X, app(XS, YS)))
active(from(X)) → mark(cons(X, from(s(X))))
active(zWadr(nil, YS)) → mark(nil)
active(zWadr(XS, nil)) → mark(nil)
active(zWadr(cons(X, XS), cons(Y, YS))) → mark(cons(app(Y, cons(X, nil)), zWadr(XS, YS)))
active(prefix(L)) → mark(cons(nil, zWadr(L, prefix(L))))
active(app(X1, X2)) → app(active(X1), X2)
active(app(X1, X2)) → app(X1, active(X2))
active(cons(X1, X2)) → cons(active(X1), X2)
active(from(X)) → from(active(X))
active(s(X)) → s(active(X))
active(zWadr(X1, X2)) → zWadr(active(X1), X2)
active(zWadr(X1, X2)) → zWadr(X1, active(X2))
active(prefix(X)) → prefix(active(X))
proper(app(X1, X2)) → app(proper(X1), proper(X2))
proper(cons(X1, X2)) → cons(proper(X1), proper(X2))
proper(from(X)) → from(proper(X))
proper(s(X)) → s(proper(X))
proper(zWadr(X1, X2)) → zWadr(proper(X1), proper(X2))
proper(prefix(X)) → prefix(proper(X))

(2) Obligation:

The Runtime Complexity (innermost) of the given CpxTRS could be proven to be BOUNDS(1, n^1).


The TRS R consists of the following rules:

top(ok(X)) → top(active(X))
proper(nil) → ok(nil)
from(ok(X)) → ok(from(X))
from(mark(X)) → mark(from(X))
app(mark(X1), X2) → mark(app(X1, X2))
app(X1, mark(X2)) → mark(app(X1, X2))
cons(ok(X1), ok(X2)) → ok(cons(X1, X2))
app(ok(X1), ok(X2)) → ok(app(X1, X2))
zWadr(ok(X1), ok(X2)) → ok(zWadr(X1, X2))
zWadr(mark(X1), X2) → mark(zWadr(X1, X2))
s(ok(X)) → ok(s(X))
s(mark(X)) → mark(s(X))
prefix(ok(X)) → ok(prefix(X))
zWadr(X1, mark(X2)) → mark(zWadr(X1, X2))
prefix(mark(X)) → mark(prefix(X))
cons(mark(X1), X2) → mark(cons(X1, X2))
top(mark(X)) → top(proper(X))

Rewrite Strategy: INNERMOST

(3) CpxTrsMatchBoundsTAProof (EQUIVALENT transformation)

A linear upper bound on the runtime complexity of the TRS R could be shown with a Match-Bound[TAB_LEFTLINEAR,TAB_NONLEFTLINEAR] (for contructor-based start-terms) of 2.

The compatible tree automaton used to show the Match-Boundedness (for constructor-based start-terms) is represented by:
final states : [1, 2, 3, 4, 5, 6, 7, 8]
transitions:
ok0(0) → 0
active0(0) → 0
nil0() → 0
mark0(0) → 0
top0(0) → 1
proper0(0) → 2
from0(0) → 3
app0(0, 0) → 4
cons0(0, 0) → 5
zWadr0(0, 0) → 6
s0(0) → 7
prefix0(0) → 8
active1(0) → 9
top1(9) → 1
nil1() → 10
ok1(10) → 2
from1(0) → 11
ok1(11) → 3
from1(0) → 12
mark1(12) → 3
app1(0, 0) → 13
mark1(13) → 4
cons1(0, 0) → 14
ok1(14) → 5
app1(0, 0) → 15
ok1(15) → 4
zWadr1(0, 0) → 16
ok1(16) → 6
zWadr1(0, 0) → 17
mark1(17) → 6
s1(0) → 18
ok1(18) → 7
s1(0) → 19
mark1(19) → 7
prefix1(0) → 20
ok1(20) → 8
prefix1(0) → 21
mark1(21) → 8
cons1(0, 0) → 22
mark1(22) → 5
proper1(0) → 23
top1(23) → 1
ok1(10) → 23
ok1(11) → 11
ok1(11) → 12
mark1(12) → 11
mark1(12) → 12
mark1(13) → 13
mark1(13) → 15
ok1(14) → 14
ok1(14) → 22
ok1(15) → 13
ok1(15) → 15
ok1(16) → 16
ok1(16) → 17
mark1(17) → 16
mark1(17) → 17
ok1(18) → 18
ok1(18) → 19
mark1(19) → 18
mark1(19) → 19
ok1(20) → 20
ok1(20) → 21
mark1(21) → 20
mark1(21) → 21
mark1(22) → 14
mark1(22) → 22
active2(10) → 24
top2(24) → 1

(4) BOUNDS(1, n^1)

(5) CpxTrsToCdtProof (BOTH BOUNDS(ID, ID) transformation)

Converted Cpx (relative) TRS to CDT

(6) Obligation:

Complexity Dependency Tuples Problem
Rules:

top(ok(z0)) → top(active(z0))
top(mark(z0)) → top(proper(z0))
proper(nil) → ok(nil)
from(ok(z0)) → ok(from(z0))
from(mark(z0)) → mark(from(z0))
app(mark(z0), z1) → mark(app(z0, z1))
app(z0, mark(z1)) → mark(app(z0, z1))
app(ok(z0), ok(z1)) → ok(app(z0, z1))
cons(ok(z0), ok(z1)) → ok(cons(z0, z1))
cons(mark(z0), z1) → mark(cons(z0, z1))
zWadr(ok(z0), ok(z1)) → ok(zWadr(z0, z1))
zWadr(mark(z0), z1) → mark(zWadr(z0, z1))
zWadr(z0, mark(z1)) → mark(zWadr(z0, z1))
s(ok(z0)) → ok(s(z0))
s(mark(z0)) → mark(s(z0))
prefix(ok(z0)) → ok(prefix(z0))
prefix(mark(z0)) → mark(prefix(z0))
Tuples:

TOP(ok(z0)) → c(TOP(active(z0)))
TOP(mark(z0)) → c1(TOP(proper(z0)), PROPER(z0))
PROPER(nil) → c2
FROM(ok(z0)) → c3(FROM(z0))
FROM(mark(z0)) → c4(FROM(z0))
APP(mark(z0), z1) → c5(APP(z0, z1))
APP(z0, mark(z1)) → c6(APP(z0, z1))
APP(ok(z0), ok(z1)) → c7(APP(z0, z1))
CONS(ok(z0), ok(z1)) → c8(CONS(z0, z1))
CONS(mark(z0), z1) → c9(CONS(z0, z1))
ZWADR(ok(z0), ok(z1)) → c10(ZWADR(z0, z1))
ZWADR(mark(z0), z1) → c11(ZWADR(z0, z1))
ZWADR(z0, mark(z1)) → c12(ZWADR(z0, z1))
S(ok(z0)) → c13(S(z0))
S(mark(z0)) → c14(S(z0))
PREFIX(ok(z0)) → c15(PREFIX(z0))
PREFIX(mark(z0)) → c16(PREFIX(z0))
S tuples:

TOP(ok(z0)) → c(TOP(active(z0)))
TOP(mark(z0)) → c1(TOP(proper(z0)), PROPER(z0))
PROPER(nil) → c2
FROM(ok(z0)) → c3(FROM(z0))
FROM(mark(z0)) → c4(FROM(z0))
APP(mark(z0), z1) → c5(APP(z0, z1))
APP(z0, mark(z1)) → c6(APP(z0, z1))
APP(ok(z0), ok(z1)) → c7(APP(z0, z1))
CONS(ok(z0), ok(z1)) → c8(CONS(z0, z1))
CONS(mark(z0), z1) → c9(CONS(z0, z1))
ZWADR(ok(z0), ok(z1)) → c10(ZWADR(z0, z1))
ZWADR(mark(z0), z1) → c11(ZWADR(z0, z1))
ZWADR(z0, mark(z1)) → c12(ZWADR(z0, z1))
S(ok(z0)) → c13(S(z0))
S(mark(z0)) → c14(S(z0))
PREFIX(ok(z0)) → c15(PREFIX(z0))
PREFIX(mark(z0)) → c16(PREFIX(z0))
K tuples:none
Defined Rule Symbols:

top, proper, from, app, cons, zWadr, s, prefix

Defined Pair Symbols:

TOP, PROPER, FROM, APP, CONS, ZWADR, S, PREFIX

Compound Symbols:

c, c1, c2, c3, c4, c5, c6, c7, c8, c9, c10, c11, c12, c13, c14, c15, c16

(7) CdtLeafRemovalProof (BOTH BOUNDS(ID, ID) transformation)

Removed 2 trailing nodes:

PROPER(nil) → c2
TOP(ok(z0)) → c(TOP(active(z0)))

(8) Obligation:

Complexity Dependency Tuples Problem
Rules:

top(ok(z0)) → top(active(z0))
top(mark(z0)) → top(proper(z0))
proper(nil) → ok(nil)
from(ok(z0)) → ok(from(z0))
from(mark(z0)) → mark(from(z0))
app(mark(z0), z1) → mark(app(z0, z1))
app(z0, mark(z1)) → mark(app(z0, z1))
app(ok(z0), ok(z1)) → ok(app(z0, z1))
cons(ok(z0), ok(z1)) → ok(cons(z0, z1))
cons(mark(z0), z1) → mark(cons(z0, z1))
zWadr(ok(z0), ok(z1)) → ok(zWadr(z0, z1))
zWadr(mark(z0), z1) → mark(zWadr(z0, z1))
zWadr(z0, mark(z1)) → mark(zWadr(z0, z1))
s(ok(z0)) → ok(s(z0))
s(mark(z0)) → mark(s(z0))
prefix(ok(z0)) → ok(prefix(z0))
prefix(mark(z0)) → mark(prefix(z0))
Tuples:

TOP(mark(z0)) → c1(TOP(proper(z0)), PROPER(z0))
FROM(ok(z0)) → c3(FROM(z0))
FROM(mark(z0)) → c4(FROM(z0))
APP(mark(z0), z1) → c5(APP(z0, z1))
APP(z0, mark(z1)) → c6(APP(z0, z1))
APP(ok(z0), ok(z1)) → c7(APP(z0, z1))
CONS(ok(z0), ok(z1)) → c8(CONS(z0, z1))
CONS(mark(z0), z1) → c9(CONS(z0, z1))
ZWADR(ok(z0), ok(z1)) → c10(ZWADR(z0, z1))
ZWADR(mark(z0), z1) → c11(ZWADR(z0, z1))
ZWADR(z0, mark(z1)) → c12(ZWADR(z0, z1))
S(ok(z0)) → c13(S(z0))
S(mark(z0)) → c14(S(z0))
PREFIX(ok(z0)) → c15(PREFIX(z0))
PREFIX(mark(z0)) → c16(PREFIX(z0))
S tuples:

TOP(mark(z0)) → c1(TOP(proper(z0)), PROPER(z0))
FROM(ok(z0)) → c3(FROM(z0))
FROM(mark(z0)) → c4(FROM(z0))
APP(mark(z0), z1) → c5(APP(z0, z1))
APP(z0, mark(z1)) → c6(APP(z0, z1))
APP(ok(z0), ok(z1)) → c7(APP(z0, z1))
CONS(ok(z0), ok(z1)) → c8(CONS(z0, z1))
CONS(mark(z0), z1) → c9(CONS(z0, z1))
ZWADR(ok(z0), ok(z1)) → c10(ZWADR(z0, z1))
ZWADR(mark(z0), z1) → c11(ZWADR(z0, z1))
ZWADR(z0, mark(z1)) → c12(ZWADR(z0, z1))
S(ok(z0)) → c13(S(z0))
S(mark(z0)) → c14(S(z0))
PREFIX(ok(z0)) → c15(PREFIX(z0))
PREFIX(mark(z0)) → c16(PREFIX(z0))
K tuples:none
Defined Rule Symbols:

top, proper, from, app, cons, zWadr, s, prefix

Defined Pair Symbols:

TOP, FROM, APP, CONS, ZWADR, S, PREFIX

Compound Symbols:

c1, c3, c4, c5, c6, c7, c8, c9, c10, c11, c12, c13, c14, c15, c16

(9) CdtRhsSimplificationProcessorProof (BOTH BOUNDS(ID, ID) transformation)

Removed 1 trailing tuple parts

(10) Obligation:

Complexity Dependency Tuples Problem
Rules:

top(ok(z0)) → top(active(z0))
top(mark(z0)) → top(proper(z0))
proper(nil) → ok(nil)
from(ok(z0)) → ok(from(z0))
from(mark(z0)) → mark(from(z0))
app(mark(z0), z1) → mark(app(z0, z1))
app(z0, mark(z1)) → mark(app(z0, z1))
app(ok(z0), ok(z1)) → ok(app(z0, z1))
cons(ok(z0), ok(z1)) → ok(cons(z0, z1))
cons(mark(z0), z1) → mark(cons(z0, z1))
zWadr(ok(z0), ok(z1)) → ok(zWadr(z0, z1))
zWadr(mark(z0), z1) → mark(zWadr(z0, z1))
zWadr(z0, mark(z1)) → mark(zWadr(z0, z1))
s(ok(z0)) → ok(s(z0))
s(mark(z0)) → mark(s(z0))
prefix(ok(z0)) → ok(prefix(z0))
prefix(mark(z0)) → mark(prefix(z0))
Tuples:

FROM(ok(z0)) → c3(FROM(z0))
FROM(mark(z0)) → c4(FROM(z0))
APP(mark(z0), z1) → c5(APP(z0, z1))
APP(z0, mark(z1)) → c6(APP(z0, z1))
APP(ok(z0), ok(z1)) → c7(APP(z0, z1))
CONS(ok(z0), ok(z1)) → c8(CONS(z0, z1))
CONS(mark(z0), z1) → c9(CONS(z0, z1))
ZWADR(ok(z0), ok(z1)) → c10(ZWADR(z0, z1))
ZWADR(mark(z0), z1) → c11(ZWADR(z0, z1))
ZWADR(z0, mark(z1)) → c12(ZWADR(z0, z1))
S(ok(z0)) → c13(S(z0))
S(mark(z0)) → c14(S(z0))
PREFIX(ok(z0)) → c15(PREFIX(z0))
PREFIX(mark(z0)) → c16(PREFIX(z0))
TOP(mark(z0)) → c1(TOP(proper(z0)))
S tuples:

FROM(ok(z0)) → c3(FROM(z0))
FROM(mark(z0)) → c4(FROM(z0))
APP(mark(z0), z1) → c5(APP(z0, z1))
APP(z0, mark(z1)) → c6(APP(z0, z1))
APP(ok(z0), ok(z1)) → c7(APP(z0, z1))
CONS(ok(z0), ok(z1)) → c8(CONS(z0, z1))
CONS(mark(z0), z1) → c9(CONS(z0, z1))
ZWADR(ok(z0), ok(z1)) → c10(ZWADR(z0, z1))
ZWADR(mark(z0), z1) → c11(ZWADR(z0, z1))
ZWADR(z0, mark(z1)) → c12(ZWADR(z0, z1))
S(ok(z0)) → c13(S(z0))
S(mark(z0)) → c14(S(z0))
PREFIX(ok(z0)) → c15(PREFIX(z0))
PREFIX(mark(z0)) → c16(PREFIX(z0))
TOP(mark(z0)) → c1(TOP(proper(z0)))
K tuples:none
Defined Rule Symbols:

top, proper, from, app, cons, zWadr, s, prefix

Defined Pair Symbols:

FROM, APP, CONS, ZWADR, S, PREFIX, TOP

Compound Symbols:

c3, c4, c5, c6, c7, c8, c9, c10, c11, c12, c13, c14, c15, c16, c1

(11) CdtUsableRulesProof (EQUIVALENT transformation)

The following rules are not usable and were removed:

top(ok(z0)) → top(active(z0))
top(mark(z0)) → top(proper(z0))
from(ok(z0)) → ok(from(z0))
from(mark(z0)) → mark(from(z0))
app(mark(z0), z1) → mark(app(z0, z1))
app(z0, mark(z1)) → mark(app(z0, z1))
app(ok(z0), ok(z1)) → ok(app(z0, z1))
cons(ok(z0), ok(z1)) → ok(cons(z0, z1))
cons(mark(z0), z1) → mark(cons(z0, z1))
zWadr(ok(z0), ok(z1)) → ok(zWadr(z0, z1))
zWadr(mark(z0), z1) → mark(zWadr(z0, z1))
zWadr(z0, mark(z1)) → mark(zWadr(z0, z1))
s(ok(z0)) → ok(s(z0))
s(mark(z0)) → mark(s(z0))
prefix(ok(z0)) → ok(prefix(z0))
prefix(mark(z0)) → mark(prefix(z0))

(12) Obligation:

Complexity Dependency Tuples Problem
Rules:

proper(nil) → ok(nil)
Tuples:

FROM(ok(z0)) → c3(FROM(z0))
FROM(mark(z0)) → c4(FROM(z0))
APP(mark(z0), z1) → c5(APP(z0, z1))
APP(z0, mark(z1)) → c6(APP(z0, z1))
APP(ok(z0), ok(z1)) → c7(APP(z0, z1))
CONS(ok(z0), ok(z1)) → c8(CONS(z0, z1))
CONS(mark(z0), z1) → c9(CONS(z0, z1))
ZWADR(ok(z0), ok(z1)) → c10(ZWADR(z0, z1))
ZWADR(mark(z0), z1) → c11(ZWADR(z0, z1))
ZWADR(z0, mark(z1)) → c12(ZWADR(z0, z1))
S(ok(z0)) → c13(S(z0))
S(mark(z0)) → c14(S(z0))
PREFIX(ok(z0)) → c15(PREFIX(z0))
PREFIX(mark(z0)) → c16(PREFIX(z0))
TOP(mark(z0)) → c1(TOP(proper(z0)))
S tuples:

FROM(ok(z0)) → c3(FROM(z0))
FROM(mark(z0)) → c4(FROM(z0))
APP(mark(z0), z1) → c5(APP(z0, z1))
APP(z0, mark(z1)) → c6(APP(z0, z1))
APP(ok(z0), ok(z1)) → c7(APP(z0, z1))
CONS(ok(z0), ok(z1)) → c8(CONS(z0, z1))
CONS(mark(z0), z1) → c9(CONS(z0, z1))
ZWADR(ok(z0), ok(z1)) → c10(ZWADR(z0, z1))
ZWADR(mark(z0), z1) → c11(ZWADR(z0, z1))
ZWADR(z0, mark(z1)) → c12(ZWADR(z0, z1))
S(ok(z0)) → c13(S(z0))
S(mark(z0)) → c14(S(z0))
PREFIX(ok(z0)) → c15(PREFIX(z0))
PREFIX(mark(z0)) → c16(PREFIX(z0))
TOP(mark(z0)) → c1(TOP(proper(z0)))
K tuples:none
Defined Rule Symbols:

proper

Defined Pair Symbols:

FROM, APP, CONS, ZWADR, S, PREFIX, TOP

Compound Symbols:

c3, c4, c5, c6, c7, c8, c9, c10, c11, c12, c13, c14, c15, c16, c1

(13) CdtRuleRemovalProof (UPPER BOUND(ADD(n^1)) transformation)

Found a reduction pair which oriented the following tuples strictly. Hence they can be removed from S.

TOP(mark(z0)) → c1(TOP(proper(z0)))
We considered the (Usable) Rules:

proper(nil) → ok(nil)
And the Tuples:

FROM(ok(z0)) → c3(FROM(z0))
FROM(mark(z0)) → c4(FROM(z0))
APP(mark(z0), z1) → c5(APP(z0, z1))
APP(z0, mark(z1)) → c6(APP(z0, z1))
APP(ok(z0), ok(z1)) → c7(APP(z0, z1))
CONS(ok(z0), ok(z1)) → c8(CONS(z0, z1))
CONS(mark(z0), z1) → c9(CONS(z0, z1))
ZWADR(ok(z0), ok(z1)) → c10(ZWADR(z0, z1))
ZWADR(mark(z0), z1) → c11(ZWADR(z0, z1))
ZWADR(z0, mark(z1)) → c12(ZWADR(z0, z1))
S(ok(z0)) → c13(S(z0))
S(mark(z0)) → c14(S(z0))
PREFIX(ok(z0)) → c15(PREFIX(z0))
PREFIX(mark(z0)) → c16(PREFIX(z0))
TOP(mark(z0)) → c1(TOP(proper(z0)))
The order we found is given by the following interpretation:
Polynomial interpretation :

POL(APP(x1, x2)) = 0   
POL(CONS(x1, x2)) = 0   
POL(FROM(x1)) = 0   
POL(PREFIX(x1)) = 0   
POL(S(x1)) = 0   
POL(TOP(x1)) = x1   
POL(ZWADR(x1, x2)) = 0   
POL(c1(x1)) = x1   
POL(c10(x1)) = x1   
POL(c11(x1)) = x1   
POL(c12(x1)) = x1   
POL(c13(x1)) = x1   
POL(c14(x1)) = x1   
POL(c15(x1)) = x1   
POL(c16(x1)) = x1   
POL(c3(x1)) = x1   
POL(c4(x1)) = x1   
POL(c5(x1)) = x1   
POL(c6(x1)) = x1   
POL(c7(x1)) = x1   
POL(c8(x1)) = x1   
POL(c9(x1)) = x1   
POL(mark(x1)) = [1] + x1   
POL(nil) = 0   
POL(ok(x1)) = 0   
POL(proper(x1)) = 0   

(14) Obligation:

Complexity Dependency Tuples Problem
Rules:

proper(nil) → ok(nil)
Tuples:

FROM(ok(z0)) → c3(FROM(z0))
FROM(mark(z0)) → c4(FROM(z0))
APP(mark(z0), z1) → c5(APP(z0, z1))
APP(z0, mark(z1)) → c6(APP(z0, z1))
APP(ok(z0), ok(z1)) → c7(APP(z0, z1))
CONS(ok(z0), ok(z1)) → c8(CONS(z0, z1))
CONS(mark(z0), z1) → c9(CONS(z0, z1))
ZWADR(ok(z0), ok(z1)) → c10(ZWADR(z0, z1))
ZWADR(mark(z0), z1) → c11(ZWADR(z0, z1))
ZWADR(z0, mark(z1)) → c12(ZWADR(z0, z1))
S(ok(z0)) → c13(S(z0))
S(mark(z0)) → c14(S(z0))
PREFIX(ok(z0)) → c15(PREFIX(z0))
PREFIX(mark(z0)) → c16(PREFIX(z0))
TOP(mark(z0)) → c1(TOP(proper(z0)))
S tuples:

FROM(ok(z0)) → c3(FROM(z0))
FROM(mark(z0)) → c4(FROM(z0))
APP(mark(z0), z1) → c5(APP(z0, z1))
APP(z0, mark(z1)) → c6(APP(z0, z1))
APP(ok(z0), ok(z1)) → c7(APP(z0, z1))
CONS(ok(z0), ok(z1)) → c8(CONS(z0, z1))
CONS(mark(z0), z1) → c9(CONS(z0, z1))
ZWADR(ok(z0), ok(z1)) → c10(ZWADR(z0, z1))
ZWADR(mark(z0), z1) → c11(ZWADR(z0, z1))
ZWADR(z0, mark(z1)) → c12(ZWADR(z0, z1))
S(ok(z0)) → c13(S(z0))
S(mark(z0)) → c14(S(z0))
PREFIX(ok(z0)) → c15(PREFIX(z0))
PREFIX(mark(z0)) → c16(PREFIX(z0))
K tuples:

TOP(mark(z0)) → c1(TOP(proper(z0)))
Defined Rule Symbols:

proper

Defined Pair Symbols:

FROM, APP, CONS, ZWADR, S, PREFIX, TOP

Compound Symbols:

c3, c4, c5, c6, c7, c8, c9, c10, c11, c12, c13, c14, c15, c16, c1

(15) CdtRuleRemovalProof (UPPER BOUND(ADD(n^1)) transformation)

Found a reduction pair which oriented the following tuples strictly. Hence they can be removed from S.

APP(mark(z0), z1) → c5(APP(z0, z1))
APP(ok(z0), ok(z1)) → c7(APP(z0, z1))
ZWADR(ok(z0), ok(z1)) → c10(ZWADR(z0, z1))
ZWADR(mark(z0), z1) → c11(ZWADR(z0, z1))
We considered the (Usable) Rules:none
And the Tuples:

FROM(ok(z0)) → c3(FROM(z0))
FROM(mark(z0)) → c4(FROM(z0))
APP(mark(z0), z1) → c5(APP(z0, z1))
APP(z0, mark(z1)) → c6(APP(z0, z1))
APP(ok(z0), ok(z1)) → c7(APP(z0, z1))
CONS(ok(z0), ok(z1)) → c8(CONS(z0, z1))
CONS(mark(z0), z1) → c9(CONS(z0, z1))
ZWADR(ok(z0), ok(z1)) → c10(ZWADR(z0, z1))
ZWADR(mark(z0), z1) → c11(ZWADR(z0, z1))
ZWADR(z0, mark(z1)) → c12(ZWADR(z0, z1))
S(ok(z0)) → c13(S(z0))
S(mark(z0)) → c14(S(z0))
PREFIX(ok(z0)) → c15(PREFIX(z0))
PREFIX(mark(z0)) → c16(PREFIX(z0))
TOP(mark(z0)) → c1(TOP(proper(z0)))
The order we found is given by the following interpretation:
Polynomial interpretation :

POL(APP(x1, x2)) = x1   
POL(CONS(x1, x2)) = 0   
POL(FROM(x1)) = 0   
POL(PREFIX(x1)) = 0   
POL(S(x1)) = 0   
POL(TOP(x1)) = 0   
POL(ZWADR(x1, x2)) = x1   
POL(c1(x1)) = x1   
POL(c10(x1)) = x1   
POL(c11(x1)) = x1   
POL(c12(x1)) = x1   
POL(c13(x1)) = x1   
POL(c14(x1)) = x1   
POL(c15(x1)) = x1   
POL(c16(x1)) = x1   
POL(c3(x1)) = x1   
POL(c4(x1)) = x1   
POL(c5(x1)) = x1   
POL(c6(x1)) = x1   
POL(c7(x1)) = x1   
POL(c8(x1)) = x1   
POL(c9(x1)) = x1   
POL(mark(x1)) = [1] + x1   
POL(nil) = 0   
POL(ok(x1)) = [1] + x1   
POL(proper(x1)) = 0   

(16) Obligation:

Complexity Dependency Tuples Problem
Rules:

proper(nil) → ok(nil)
Tuples:

FROM(ok(z0)) → c3(FROM(z0))
FROM(mark(z0)) → c4(FROM(z0))
APP(mark(z0), z1) → c5(APP(z0, z1))
APP(z0, mark(z1)) → c6(APP(z0, z1))
APP(ok(z0), ok(z1)) → c7(APP(z0, z1))
CONS(ok(z0), ok(z1)) → c8(CONS(z0, z1))
CONS(mark(z0), z1) → c9(CONS(z0, z1))
ZWADR(ok(z0), ok(z1)) → c10(ZWADR(z0, z1))
ZWADR(mark(z0), z1) → c11(ZWADR(z0, z1))
ZWADR(z0, mark(z1)) → c12(ZWADR(z0, z1))
S(ok(z0)) → c13(S(z0))
S(mark(z0)) → c14(S(z0))
PREFIX(ok(z0)) → c15(PREFIX(z0))
PREFIX(mark(z0)) → c16(PREFIX(z0))
TOP(mark(z0)) → c1(TOP(proper(z0)))
S tuples:

FROM(ok(z0)) → c3(FROM(z0))
FROM(mark(z0)) → c4(FROM(z0))
APP(z0, mark(z1)) → c6(APP(z0, z1))
CONS(ok(z0), ok(z1)) → c8(CONS(z0, z1))
CONS(mark(z0), z1) → c9(CONS(z0, z1))
ZWADR(z0, mark(z1)) → c12(ZWADR(z0, z1))
S(ok(z0)) → c13(S(z0))
S(mark(z0)) → c14(S(z0))
PREFIX(ok(z0)) → c15(PREFIX(z0))
PREFIX(mark(z0)) → c16(PREFIX(z0))
K tuples:

TOP(mark(z0)) → c1(TOP(proper(z0)))
APP(mark(z0), z1) → c5(APP(z0, z1))
APP(ok(z0), ok(z1)) → c7(APP(z0, z1))
ZWADR(ok(z0), ok(z1)) → c10(ZWADR(z0, z1))
ZWADR(mark(z0), z1) → c11(ZWADR(z0, z1))
Defined Rule Symbols:

proper

Defined Pair Symbols:

FROM, APP, CONS, ZWADR, S, PREFIX, TOP

Compound Symbols:

c3, c4, c5, c6, c7, c8, c9, c10, c11, c12, c13, c14, c15, c16, c1

(17) CdtRuleRemovalProof (UPPER BOUND(ADD(n^1)) transformation)

Found a reduction pair which oriented the following tuples strictly. Hence they can be removed from S.

FROM(ok(z0)) → c3(FROM(z0))
PREFIX(ok(z0)) → c15(PREFIX(z0))
We considered the (Usable) Rules:none
And the Tuples:

FROM(ok(z0)) → c3(FROM(z0))
FROM(mark(z0)) → c4(FROM(z0))
APP(mark(z0), z1) → c5(APP(z0, z1))
APP(z0, mark(z1)) → c6(APP(z0, z1))
APP(ok(z0), ok(z1)) → c7(APP(z0, z1))
CONS(ok(z0), ok(z1)) → c8(CONS(z0, z1))
CONS(mark(z0), z1) → c9(CONS(z0, z1))
ZWADR(ok(z0), ok(z1)) → c10(ZWADR(z0, z1))
ZWADR(mark(z0), z1) → c11(ZWADR(z0, z1))
ZWADR(z0, mark(z1)) → c12(ZWADR(z0, z1))
S(ok(z0)) → c13(S(z0))
S(mark(z0)) → c14(S(z0))
PREFIX(ok(z0)) → c15(PREFIX(z0))
PREFIX(mark(z0)) → c16(PREFIX(z0))
TOP(mark(z0)) → c1(TOP(proper(z0)))
The order we found is given by the following interpretation:
Polynomial interpretation :

POL(APP(x1, x2)) = 0   
POL(CONS(x1, x2)) = 0   
POL(FROM(x1)) = x1   
POL(PREFIX(x1)) = [2]x1   
POL(S(x1)) = 0   
POL(TOP(x1)) = 0   
POL(ZWADR(x1, x2)) = 0   
POL(c1(x1)) = x1   
POL(c10(x1)) = x1   
POL(c11(x1)) = x1   
POL(c12(x1)) = x1   
POL(c13(x1)) = x1   
POL(c14(x1)) = x1   
POL(c15(x1)) = x1   
POL(c16(x1)) = x1   
POL(c3(x1)) = x1   
POL(c4(x1)) = x1   
POL(c5(x1)) = x1   
POL(c6(x1)) = x1   
POL(c7(x1)) = x1   
POL(c8(x1)) = x1   
POL(c9(x1)) = x1   
POL(mark(x1)) = x1   
POL(nil) = 0   
POL(ok(x1)) = [1] + x1   
POL(proper(x1)) = 0   

(18) Obligation:

Complexity Dependency Tuples Problem
Rules:

proper(nil) → ok(nil)
Tuples:

FROM(ok(z0)) → c3(FROM(z0))
FROM(mark(z0)) → c4(FROM(z0))
APP(mark(z0), z1) → c5(APP(z0, z1))
APP(z0, mark(z1)) → c6(APP(z0, z1))
APP(ok(z0), ok(z1)) → c7(APP(z0, z1))
CONS(ok(z0), ok(z1)) → c8(CONS(z0, z1))
CONS(mark(z0), z1) → c9(CONS(z0, z1))
ZWADR(ok(z0), ok(z1)) → c10(ZWADR(z0, z1))
ZWADR(mark(z0), z1) → c11(ZWADR(z0, z1))
ZWADR(z0, mark(z1)) → c12(ZWADR(z0, z1))
S(ok(z0)) → c13(S(z0))
S(mark(z0)) → c14(S(z0))
PREFIX(ok(z0)) → c15(PREFIX(z0))
PREFIX(mark(z0)) → c16(PREFIX(z0))
TOP(mark(z0)) → c1(TOP(proper(z0)))
S tuples:

FROM(mark(z0)) → c4(FROM(z0))
APP(z0, mark(z1)) → c6(APP(z0, z1))
CONS(ok(z0), ok(z1)) → c8(CONS(z0, z1))
CONS(mark(z0), z1) → c9(CONS(z0, z1))
ZWADR(z0, mark(z1)) → c12(ZWADR(z0, z1))
S(ok(z0)) → c13(S(z0))
S(mark(z0)) → c14(S(z0))
PREFIX(mark(z0)) → c16(PREFIX(z0))
K tuples:

TOP(mark(z0)) → c1(TOP(proper(z0)))
APP(mark(z0), z1) → c5(APP(z0, z1))
APP(ok(z0), ok(z1)) → c7(APP(z0, z1))
ZWADR(ok(z0), ok(z1)) → c10(ZWADR(z0, z1))
ZWADR(mark(z0), z1) → c11(ZWADR(z0, z1))
FROM(ok(z0)) → c3(FROM(z0))
PREFIX(ok(z0)) → c15(PREFIX(z0))
Defined Rule Symbols:

proper

Defined Pair Symbols:

FROM, APP, CONS, ZWADR, S, PREFIX, TOP

Compound Symbols:

c3, c4, c5, c6, c7, c8, c9, c10, c11, c12, c13, c14, c15, c16, c1

(19) CdtRuleRemovalProof (UPPER BOUND(ADD(n^1)) transformation)

Found a reduction pair which oriented the following tuples strictly. Hence they can be removed from S.

FROM(mark(z0)) → c4(FROM(z0))
CONS(ok(z0), ok(z1)) → c8(CONS(z0, z1))
ZWADR(z0, mark(z1)) → c12(ZWADR(z0, z1))
S(ok(z0)) → c13(S(z0))
S(mark(z0)) → c14(S(z0))
We considered the (Usable) Rules:none
And the Tuples:

FROM(ok(z0)) → c3(FROM(z0))
FROM(mark(z0)) → c4(FROM(z0))
APP(mark(z0), z1) → c5(APP(z0, z1))
APP(z0, mark(z1)) → c6(APP(z0, z1))
APP(ok(z0), ok(z1)) → c7(APP(z0, z1))
CONS(ok(z0), ok(z1)) → c8(CONS(z0, z1))
CONS(mark(z0), z1) → c9(CONS(z0, z1))
ZWADR(ok(z0), ok(z1)) → c10(ZWADR(z0, z1))
ZWADR(mark(z0), z1) → c11(ZWADR(z0, z1))
ZWADR(z0, mark(z1)) → c12(ZWADR(z0, z1))
S(ok(z0)) → c13(S(z0))
S(mark(z0)) → c14(S(z0))
PREFIX(ok(z0)) → c15(PREFIX(z0))
PREFIX(mark(z0)) → c16(PREFIX(z0))
TOP(mark(z0)) → c1(TOP(proper(z0)))
The order we found is given by the following interpretation:
Polynomial interpretation :

POL(APP(x1, x2)) = 0   
POL(CONS(x1, x2)) = x2   
POL(FROM(x1)) = x1   
POL(PREFIX(x1)) = 0   
POL(S(x1)) = x1   
POL(TOP(x1)) = 0   
POL(ZWADR(x1, x2)) = x2   
POL(c1(x1)) = x1   
POL(c10(x1)) = x1   
POL(c11(x1)) = x1   
POL(c12(x1)) = x1   
POL(c13(x1)) = x1   
POL(c14(x1)) = x1   
POL(c15(x1)) = x1   
POL(c16(x1)) = x1   
POL(c3(x1)) = x1   
POL(c4(x1)) = x1   
POL(c5(x1)) = x1   
POL(c6(x1)) = x1   
POL(c7(x1)) = x1   
POL(c8(x1)) = x1   
POL(c9(x1)) = x1   
POL(mark(x1)) = [1] + x1   
POL(nil) = 0   
POL(ok(x1)) = [1] + x1   
POL(proper(x1)) = 0   

(20) Obligation:

Complexity Dependency Tuples Problem
Rules:

proper(nil) → ok(nil)
Tuples:

FROM(ok(z0)) → c3(FROM(z0))
FROM(mark(z0)) → c4(FROM(z0))
APP(mark(z0), z1) → c5(APP(z0, z1))
APP(z0, mark(z1)) → c6(APP(z0, z1))
APP(ok(z0), ok(z1)) → c7(APP(z0, z1))
CONS(ok(z0), ok(z1)) → c8(CONS(z0, z1))
CONS(mark(z0), z1) → c9(CONS(z0, z1))
ZWADR(ok(z0), ok(z1)) → c10(ZWADR(z0, z1))
ZWADR(mark(z0), z1) → c11(ZWADR(z0, z1))
ZWADR(z0, mark(z1)) → c12(ZWADR(z0, z1))
S(ok(z0)) → c13(S(z0))
S(mark(z0)) → c14(S(z0))
PREFIX(ok(z0)) → c15(PREFIX(z0))
PREFIX(mark(z0)) → c16(PREFIX(z0))
TOP(mark(z0)) → c1(TOP(proper(z0)))
S tuples:

APP(z0, mark(z1)) → c6(APP(z0, z1))
CONS(mark(z0), z1) → c9(CONS(z0, z1))
PREFIX(mark(z0)) → c16(PREFIX(z0))
K tuples:

TOP(mark(z0)) → c1(TOP(proper(z0)))
APP(mark(z0), z1) → c5(APP(z0, z1))
APP(ok(z0), ok(z1)) → c7(APP(z0, z1))
ZWADR(ok(z0), ok(z1)) → c10(ZWADR(z0, z1))
ZWADR(mark(z0), z1) → c11(ZWADR(z0, z1))
FROM(ok(z0)) → c3(FROM(z0))
PREFIX(ok(z0)) → c15(PREFIX(z0))
FROM(mark(z0)) → c4(FROM(z0))
CONS(ok(z0), ok(z1)) → c8(CONS(z0, z1))
ZWADR(z0, mark(z1)) → c12(ZWADR(z0, z1))
S(ok(z0)) → c13(S(z0))
S(mark(z0)) → c14(S(z0))
Defined Rule Symbols:

proper

Defined Pair Symbols:

FROM, APP, CONS, ZWADR, S, PREFIX, TOP

Compound Symbols:

c3, c4, c5, c6, c7, c8, c9, c10, c11, c12, c13, c14, c15, c16, c1

(21) CdtRuleRemovalProof (UPPER BOUND(ADD(n^1)) transformation)

Found a reduction pair which oriented the following tuples strictly. Hence they can be removed from S.

PREFIX(mark(z0)) → c16(PREFIX(z0))
We considered the (Usable) Rules:none
And the Tuples:

FROM(ok(z0)) → c3(FROM(z0))
FROM(mark(z0)) → c4(FROM(z0))
APP(mark(z0), z1) → c5(APP(z0, z1))
APP(z0, mark(z1)) → c6(APP(z0, z1))
APP(ok(z0), ok(z1)) → c7(APP(z0, z1))
CONS(ok(z0), ok(z1)) → c8(CONS(z0, z1))
CONS(mark(z0), z1) → c9(CONS(z0, z1))
ZWADR(ok(z0), ok(z1)) → c10(ZWADR(z0, z1))
ZWADR(mark(z0), z1) → c11(ZWADR(z0, z1))
ZWADR(z0, mark(z1)) → c12(ZWADR(z0, z1))
S(ok(z0)) → c13(S(z0))
S(mark(z0)) → c14(S(z0))
PREFIX(ok(z0)) → c15(PREFIX(z0))
PREFIX(mark(z0)) → c16(PREFIX(z0))
TOP(mark(z0)) → c1(TOP(proper(z0)))
The order we found is given by the following interpretation:
Polynomial interpretation :

POL(APP(x1, x2)) = 0   
POL(CONS(x1, x2)) = 0   
POL(FROM(x1)) = 0   
POL(PREFIX(x1)) = x1   
POL(S(x1)) = 0   
POL(TOP(x1)) = 0   
POL(ZWADR(x1, x2)) = 0   
POL(c1(x1)) = x1   
POL(c10(x1)) = x1   
POL(c11(x1)) = x1   
POL(c12(x1)) = x1   
POL(c13(x1)) = x1   
POL(c14(x1)) = x1   
POL(c15(x1)) = x1   
POL(c16(x1)) = x1   
POL(c3(x1)) = x1   
POL(c4(x1)) = x1   
POL(c5(x1)) = x1   
POL(c6(x1)) = x1   
POL(c7(x1)) = x1   
POL(c8(x1)) = x1   
POL(c9(x1)) = x1   
POL(mark(x1)) = [1] + x1   
POL(nil) = 0   
POL(ok(x1)) = x1   
POL(proper(x1)) = 0   

(22) Obligation:

Complexity Dependency Tuples Problem
Rules:

proper(nil) → ok(nil)
Tuples:

FROM(ok(z0)) → c3(FROM(z0))
FROM(mark(z0)) → c4(FROM(z0))
APP(mark(z0), z1) → c5(APP(z0, z1))
APP(z0, mark(z1)) → c6(APP(z0, z1))
APP(ok(z0), ok(z1)) → c7(APP(z0, z1))
CONS(ok(z0), ok(z1)) → c8(CONS(z0, z1))
CONS(mark(z0), z1) → c9(CONS(z0, z1))
ZWADR(ok(z0), ok(z1)) → c10(ZWADR(z0, z1))
ZWADR(mark(z0), z1) → c11(ZWADR(z0, z1))
ZWADR(z0, mark(z1)) → c12(ZWADR(z0, z1))
S(ok(z0)) → c13(S(z0))
S(mark(z0)) → c14(S(z0))
PREFIX(ok(z0)) → c15(PREFIX(z0))
PREFIX(mark(z0)) → c16(PREFIX(z0))
TOP(mark(z0)) → c1(TOP(proper(z0)))
S tuples:

APP(z0, mark(z1)) → c6(APP(z0, z1))
CONS(mark(z0), z1) → c9(CONS(z0, z1))
K tuples:

TOP(mark(z0)) → c1(TOP(proper(z0)))
APP(mark(z0), z1) → c5(APP(z0, z1))
APP(ok(z0), ok(z1)) → c7(APP(z0, z1))
ZWADR(ok(z0), ok(z1)) → c10(ZWADR(z0, z1))
ZWADR(mark(z0), z1) → c11(ZWADR(z0, z1))
FROM(ok(z0)) → c3(FROM(z0))
PREFIX(ok(z0)) → c15(PREFIX(z0))
FROM(mark(z0)) → c4(FROM(z0))
CONS(ok(z0), ok(z1)) → c8(CONS(z0, z1))
ZWADR(z0, mark(z1)) → c12(ZWADR(z0, z1))
S(ok(z0)) → c13(S(z0))
S(mark(z0)) → c14(S(z0))
PREFIX(mark(z0)) → c16(PREFIX(z0))
Defined Rule Symbols:

proper

Defined Pair Symbols:

FROM, APP, CONS, ZWADR, S, PREFIX, TOP

Compound Symbols:

c3, c4, c5, c6, c7, c8, c9, c10, c11, c12, c13, c14, c15, c16, c1

(23) CdtRuleRemovalProof (UPPER BOUND(ADD(n^1)) transformation)

Found a reduction pair which oriented the following tuples strictly. Hence they can be removed from S.

CONS(mark(z0), z1) → c9(CONS(z0, z1))
We considered the (Usable) Rules:none
And the Tuples:

FROM(ok(z0)) → c3(FROM(z0))
FROM(mark(z0)) → c4(FROM(z0))
APP(mark(z0), z1) → c5(APP(z0, z1))
APP(z0, mark(z1)) → c6(APP(z0, z1))
APP(ok(z0), ok(z1)) → c7(APP(z0, z1))
CONS(ok(z0), ok(z1)) → c8(CONS(z0, z1))
CONS(mark(z0), z1) → c9(CONS(z0, z1))
ZWADR(ok(z0), ok(z1)) → c10(ZWADR(z0, z1))
ZWADR(mark(z0), z1) → c11(ZWADR(z0, z1))
ZWADR(z0, mark(z1)) → c12(ZWADR(z0, z1))
S(ok(z0)) → c13(S(z0))
S(mark(z0)) → c14(S(z0))
PREFIX(ok(z0)) → c15(PREFIX(z0))
PREFIX(mark(z0)) → c16(PREFIX(z0))
TOP(mark(z0)) → c1(TOP(proper(z0)))
The order we found is given by the following interpretation:
Polynomial interpretation :

POL(APP(x1, x2)) = 0   
POL(CONS(x1, x2)) = x1 + x2   
POL(FROM(x1)) = 0   
POL(PREFIX(x1)) = 0   
POL(S(x1)) = 0   
POL(TOP(x1)) = 0   
POL(ZWADR(x1, x2)) = 0   
POL(c1(x1)) = x1   
POL(c10(x1)) = x1   
POL(c11(x1)) = x1   
POL(c12(x1)) = x1   
POL(c13(x1)) = x1   
POL(c14(x1)) = x1   
POL(c15(x1)) = x1   
POL(c16(x1)) = x1   
POL(c3(x1)) = x1   
POL(c4(x1)) = x1   
POL(c5(x1)) = x1   
POL(c6(x1)) = x1   
POL(c7(x1)) = x1   
POL(c8(x1)) = x1   
POL(c9(x1)) = x1   
POL(mark(x1)) = [1] + x1   
POL(nil) = 0   
POL(ok(x1)) = x1   
POL(proper(x1)) = 0   

(24) Obligation:

Complexity Dependency Tuples Problem
Rules:

proper(nil) → ok(nil)
Tuples:

FROM(ok(z0)) → c3(FROM(z0))
FROM(mark(z0)) → c4(FROM(z0))
APP(mark(z0), z1) → c5(APP(z0, z1))
APP(z0, mark(z1)) → c6(APP(z0, z1))
APP(ok(z0), ok(z1)) → c7(APP(z0, z1))
CONS(ok(z0), ok(z1)) → c8(CONS(z0, z1))
CONS(mark(z0), z1) → c9(CONS(z0, z1))
ZWADR(ok(z0), ok(z1)) → c10(ZWADR(z0, z1))
ZWADR(mark(z0), z1) → c11(ZWADR(z0, z1))
ZWADR(z0, mark(z1)) → c12(ZWADR(z0, z1))
S(ok(z0)) → c13(S(z0))
S(mark(z0)) → c14(S(z0))
PREFIX(ok(z0)) → c15(PREFIX(z0))
PREFIX(mark(z0)) → c16(PREFIX(z0))
TOP(mark(z0)) → c1(TOP(proper(z0)))
S tuples:

APP(z0, mark(z1)) → c6(APP(z0, z1))
K tuples:

TOP(mark(z0)) → c1(TOP(proper(z0)))
APP(mark(z0), z1) → c5(APP(z0, z1))
APP(ok(z0), ok(z1)) → c7(APP(z0, z1))
ZWADR(ok(z0), ok(z1)) → c10(ZWADR(z0, z1))
ZWADR(mark(z0), z1) → c11(ZWADR(z0, z1))
FROM(ok(z0)) → c3(FROM(z0))
PREFIX(ok(z0)) → c15(PREFIX(z0))
FROM(mark(z0)) → c4(FROM(z0))
CONS(ok(z0), ok(z1)) → c8(CONS(z0, z1))
ZWADR(z0, mark(z1)) → c12(ZWADR(z0, z1))
S(ok(z0)) → c13(S(z0))
S(mark(z0)) → c14(S(z0))
PREFIX(mark(z0)) → c16(PREFIX(z0))
CONS(mark(z0), z1) → c9(CONS(z0, z1))
Defined Rule Symbols:

proper

Defined Pair Symbols:

FROM, APP, CONS, ZWADR, S, PREFIX, TOP

Compound Symbols:

c3, c4, c5, c6, c7, c8, c9, c10, c11, c12, c13, c14, c15, c16, c1

(25) CdtRuleRemovalProof (UPPER BOUND(ADD(n^1)) transformation)

Found a reduction pair which oriented the following tuples strictly. Hence they can be removed from S.

APP(z0, mark(z1)) → c6(APP(z0, z1))
We considered the (Usable) Rules:none
And the Tuples:

FROM(ok(z0)) → c3(FROM(z0))
FROM(mark(z0)) → c4(FROM(z0))
APP(mark(z0), z1) → c5(APP(z0, z1))
APP(z0, mark(z1)) → c6(APP(z0, z1))
APP(ok(z0), ok(z1)) → c7(APP(z0, z1))
CONS(ok(z0), ok(z1)) → c8(CONS(z0, z1))
CONS(mark(z0), z1) → c9(CONS(z0, z1))
ZWADR(ok(z0), ok(z1)) → c10(ZWADR(z0, z1))
ZWADR(mark(z0), z1) → c11(ZWADR(z0, z1))
ZWADR(z0, mark(z1)) → c12(ZWADR(z0, z1))
S(ok(z0)) → c13(S(z0))
S(mark(z0)) → c14(S(z0))
PREFIX(ok(z0)) → c15(PREFIX(z0))
PREFIX(mark(z0)) → c16(PREFIX(z0))
TOP(mark(z0)) → c1(TOP(proper(z0)))
The order we found is given by the following interpretation:
Polynomial interpretation :

POL(APP(x1, x2)) = x2   
POL(CONS(x1, x2)) = 0   
POL(FROM(x1)) = 0   
POL(PREFIX(x1)) = 0   
POL(S(x1)) = 0   
POL(TOP(x1)) = 0   
POL(ZWADR(x1, x2)) = 0   
POL(c1(x1)) = x1   
POL(c10(x1)) = x1   
POL(c11(x1)) = x1   
POL(c12(x1)) = x1   
POL(c13(x1)) = x1   
POL(c14(x1)) = x1   
POL(c15(x1)) = x1   
POL(c16(x1)) = x1   
POL(c3(x1)) = x1   
POL(c4(x1)) = x1   
POL(c5(x1)) = x1   
POL(c6(x1)) = x1   
POL(c7(x1)) = x1   
POL(c8(x1)) = x1   
POL(c9(x1)) = x1   
POL(mark(x1)) = [1] + x1   
POL(nil) = 0   
POL(ok(x1)) = x1   
POL(proper(x1)) = 0   

(26) Obligation:

Complexity Dependency Tuples Problem
Rules:

proper(nil) → ok(nil)
Tuples:

FROM(ok(z0)) → c3(FROM(z0))
FROM(mark(z0)) → c4(FROM(z0))
APP(mark(z0), z1) → c5(APP(z0, z1))
APP(z0, mark(z1)) → c6(APP(z0, z1))
APP(ok(z0), ok(z1)) → c7(APP(z0, z1))
CONS(ok(z0), ok(z1)) → c8(CONS(z0, z1))
CONS(mark(z0), z1) → c9(CONS(z0, z1))
ZWADR(ok(z0), ok(z1)) → c10(ZWADR(z0, z1))
ZWADR(mark(z0), z1) → c11(ZWADR(z0, z1))
ZWADR(z0, mark(z1)) → c12(ZWADR(z0, z1))
S(ok(z0)) → c13(S(z0))
S(mark(z0)) → c14(S(z0))
PREFIX(ok(z0)) → c15(PREFIX(z0))
PREFIX(mark(z0)) → c16(PREFIX(z0))
TOP(mark(z0)) → c1(TOP(proper(z0)))
S tuples:none
K tuples:

TOP(mark(z0)) → c1(TOP(proper(z0)))
APP(mark(z0), z1) → c5(APP(z0, z1))
APP(ok(z0), ok(z1)) → c7(APP(z0, z1))
ZWADR(ok(z0), ok(z1)) → c10(ZWADR(z0, z1))
ZWADR(mark(z0), z1) → c11(ZWADR(z0, z1))
FROM(ok(z0)) → c3(FROM(z0))
PREFIX(ok(z0)) → c15(PREFIX(z0))
FROM(mark(z0)) → c4(FROM(z0))
CONS(ok(z0), ok(z1)) → c8(CONS(z0, z1))
ZWADR(z0, mark(z1)) → c12(ZWADR(z0, z1))
S(ok(z0)) → c13(S(z0))
S(mark(z0)) → c14(S(z0))
PREFIX(mark(z0)) → c16(PREFIX(z0))
CONS(mark(z0), z1) → c9(CONS(z0, z1))
APP(z0, mark(z1)) → c6(APP(z0, z1))
Defined Rule Symbols:

proper

Defined Pair Symbols:

FROM, APP, CONS, ZWADR, S, PREFIX, TOP

Compound Symbols:

c3, c4, c5, c6, c7, c8, c9, c10, c11, c12, c13, c14, c15, c16, c1

(27) SIsEmptyProof (BOTH BOUNDS(ID, ID) transformation)

The set S is empty

(28) BOUNDS(1, 1)